每日一学：下载文件根据id取url后下载

<a class="url" apkids="${apk[0]}" href="javascript:void(0);">view</a> 
$(function(){ 
    $(".url").click(function(){ 
        var apkID=$(this).attr("apkids"); 
        jQuery.ajax({ 
            type:"post", 
            url:"<c:url value='apkProToSign!getReportUrl.do'/>", 
            data:{ apkID:apkID }, 
            async:true, 
            success:function(data){ 
                if(data=='1'){ 
                    alert("No report data!"); 
                }else{ 
                    if(data.length>0){ 
                        window.location.href=data; 
                    } 
                } 
            } 
        }); 
    }) 

})